COMREL Sample "Fatigue": Problem Description
Time-variant Problem with COMREL-TI:
Use of Conditions in Failure FunctionsPreface
In this example we not only illustrate how to solve
a time variant problem with COMREL-TI but also demonstrate
a number of additional features of the symbolic processor which may
be useful in more complicated cases. Additionally, we present some remarks
on stochastic modelling for the special problem of crack propagation.
Crack growth and crack instability problems are
frequently encountered in structural reliability. The fatigue example
provided with COMREL also addresses some peculiarities
when performing such analyses. The basic formulation is for time-invariant
analysis by COMREL-TI but it can easily be modified for
a COMREL-TV application by assigning a scalar process
to the load variable S. Note, however, that the failure criterion then
should also be modified to describe crack instability.
Crack growth is defined by Paris-Ergodan´s law:
(1)
with material constants m and C.
S
is the applied random stress range. Y(a) is a geometry factor usually
depending on crack length a and containing
,
see e.g. [1]. For this example, Y(a) is the constant 1.0
and consequently Ym = pm/2. Eq. (1) can be integrated:
(2 a)
(2 b)
with k = (2 - m)/2.
For the time invariant case at hand (stationary
loading) we compute N(t) from
t (
is upcrossing rate of the mean of the load process denoted as parameter
‘Rate’, t is parameter ‘Time’). k is negative for any m > 2. Therefore,
the expression (2b) can become singular for some t and makes no sense
for times larger than this ‘explosion’ time. If the stress variation
is a narrow band Gaussian process, the stress range is Rayleigh distributed
and its expected value can be computed from:
(3)
Failure is defined if the crack depth a(t) exceeds
a critical limit acrit:
V = {acrit - a(t) <=
0} (4 a)
Abbreviating C Ym E[
Sm]
N(t) as ‘RHS’ (Right Hand Side) and using eqs.(2) the failure domain
is
(4 b)
or
(4 c)
Note the ‘check on a(t) explosion’ in the numerical
formulation in failure function. This formulation is possible because
fatigue crack growth follows a monotonic function. Then, excedance of
acrit by a(t) at time t is equivalent to the event T <
t with T the first passage time. The actual formulation of the failure
function together with several auxiliary user defined functions is given
below.
Next: Handling